3x^2-60x+150=0

Solution for 3x^2-60x+150=0 equation:

3x^2-60x+150=0

a = 3; b = -60; c = +150;
Δ = b2-4ac
Δ = -602-4·3·150
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-30\sqrt{2}}{2*3}=\frac{60-30\sqrt{2}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+30\sqrt{2}}{2*3}=\frac{60+30\sqrt{2}}{6}
$